Write a program in C to find whether the number is Armstrong number.

 Write a program to find whether the number is Armstrong number

Index

• Introduction
• Algorithm of Problem 
• Flow Chart 
• Program in C 
• Out Put

Introduction 

Armstrong number is the number whose digits cube is sum together we get the same number ex 370 in this number we have three digits 3 , 7 , 0, if we calculate the cube of each digit cube of 3 is 27, similarly cube of 7 is 343 and 0 is 0. if we add the resulted value 343+27+0=370 as answer is same as number so number is Armstrong number.

Algorithm of solving given problem

Step 1: Declare three variable digit, sum , num  

Step 2: Take  a number as input from user

Step 3: initialize the value of sum = 0 and set temp = num

Step 4: Repeat step 5 to 7  until num !=0

Step 5: Set digit = num %10;

Step 6: Set num=num / 10;

Step 7: Set sum=sum + digit * digit * digit.

Step 8: If sum == temp than

           print number is arm strong

           otherwise

           print number is not arm strong 

Step 9: Exit

Flow Chart

Flow chart 

Program in C language

#include<stdio.h>

#include<conio.h>

void main()

{

int digit,sum=0,temp,num;

  printf("enter an number\n");

  scanf("%d",&num);

   temp=num;

   while(num!=0)

   {

        digit=num%10;

        num=num/10;

        sum=sum+digit*digit*digit;

   }

   if(sum==temp)

   {

       printf("number is Armstrong");

   }

   else

   {

        printf("number is not Armstrong");

   }

}

OUTPUT

enter an number

370

number is Armstrong

enter an number

370

number is not Armstrong

Share: